Optimal. Leaf size=604 \[ -\frac{\left (a^2 f^2 \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )+4 a c d^2 f^2+c^2 d^2 \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (e-\sqrt{e^2-4 d f}\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^2 f \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{\left (a^2 f^2 \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )+4 a c d^2 f^2+c^2 d^2 \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (\sqrt{e^2-4 d f}+e\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^2 f \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{a^{3/2} e \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^2}-\frac{a e \sqrt{a+c x^2}}{d^2}+\frac{\sqrt{a+c x^2} (2 a e-c d x)}{2 d^2}+\frac{\sqrt{c} (2 c d-3 a f) \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d f}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{3 c x \sqrt{a+c x^2}}{2 d}+\frac{3 a \sqrt{c} \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d} \]
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Rubi [A] time = 2.80936, antiderivative size = 604, normalized size of antiderivative = 1., number of steps used = 21, number of rules used = 14, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.518, Rules used = {6728, 277, 195, 217, 206, 266, 50, 63, 208, 1020, 1068, 1080, 1034, 725} \[ -\frac{\left (a^2 f^2 \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )+4 a c d^2 f^2+c^2 d^2 \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (e-\sqrt{e^2-4 d f}\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^2 f \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{\left (a^2 f^2 \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )+4 a c d^2 f^2+c^2 d^2 \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (\sqrt{e^2-4 d f}+e\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^2 f \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{a^{3/2} e \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^2}-\frac{a e \sqrt{a+c x^2}}{d^2}+\frac{\sqrt{a+c x^2} (2 a e-c d x)}{2 d^2}+\frac{\sqrt{c} (2 c d-3 a f) \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d f}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{3 c x \sqrt{a+c x^2}}{2 d}+\frac{3 a \sqrt{c} \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d} \]
Antiderivative was successfully verified.
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Rule 6728
Rule 277
Rule 195
Rule 217
Rule 206
Rule 266
Rule 50
Rule 63
Rule 208
Rule 1020
Rule 1068
Rule 1080
Rule 1034
Rule 725
Rubi steps
\begin{align*} \int \frac{\left (a+c x^2\right )^{3/2}}{x^2 \left (d+e x+f x^2\right )} \, dx &=\int \left (\frac{\left (a+c x^2\right )^{3/2}}{d x^2}-\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}+\frac{\left (e^2-d f+e f x\right ) \left (a+c x^2\right )^{3/2}}{d^2 \left (d+e x+f x^2\right )}\right ) \, dx\\ &=\frac{\int \frac{\left (e^2-d f+e f x\right ) \left (a+c x^2\right )^{3/2}}{d+e x+f x^2} \, dx}{d^2}+\frac{\int \frac{\left (a+c x^2\right )^{3/2}}{x^2} \, dx}{d}-\frac{e \int \frac{\left (a+c x^2\right )^{3/2}}{x} \, dx}{d^2}\\ &=\frac{e \left (a+c x^2\right )^{3/2}}{3 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{(3 c) \int \sqrt{a+c x^2} \, dx}{d}-\frac{e \operatorname{Subst}\left (\int \frac{(a+c x)^{3/2}}{x} \, dx,x,x^2\right )}{2 d^2}+\frac{\int \frac{\sqrt{a+c x^2} \left (3 a f \left (e^2-d f\right )-3 e f (c d-a f) x-3 c d f^2 x^2\right )}{d+e x+f x^2} \, dx}{3 d^2 f}\\ &=\frac{3 c x \sqrt{a+c x^2}}{2 d}+\frac{(2 a e-c d x) \sqrt{a+c x^2}}{2 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{(3 a c) \int \frac{1}{\sqrt{a+c x^2}} \, dx}{2 d}-\frac{(a e) \operatorname{Subst}\left (\int \frac{\sqrt{a+c x}}{x} \, dx,x,x^2\right )}{2 d^2}-\frac{\int \frac{-3 a c f^3 \left (c d^2+2 a e^2-2 a d f\right )+3 a c e f^3 (3 c d-2 a f) x-3 c^2 d f^3 (2 c d-3 a f) x^2}{\sqrt{a+c x^2} \left (d+e x+f x^2\right )} \, dx}{6 c d^2 f^3}\\ &=-\frac{a e \sqrt{a+c x^2}}{d^2}+\frac{3 c x \sqrt{a+c x^2}}{2 d}+\frac{(2 a e-c d x) \sqrt{a+c x^2}}{2 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{(3 a c) \operatorname{Subst}\left (\int \frac{1}{1-c x^2} \, dx,x,\frac{x}{\sqrt{a+c x^2}}\right )}{2 d}-\frac{\left (a^2 e\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+c x}} \, dx,x,x^2\right )}{2 d^2}-\frac{\int \frac{3 c^2 d^2 f^3 (2 c d-3 a f)-3 a c f^4 \left (c d^2+2 a e^2-2 a d f\right )+\left (3 c^2 d e f^3 (2 c d-3 a f)+3 a c e f^4 (3 c d-2 a f)\right ) x}{\sqrt{a+c x^2} \left (d+e x+f x^2\right )} \, dx}{6 c d^2 f^4}+\frac{(c (2 c d-3 a f)) \int \frac{1}{\sqrt{a+c x^2}} \, dx}{2 d f}\\ &=-\frac{a e \sqrt{a+c x^2}}{d^2}+\frac{3 c x \sqrt{a+c x^2}}{2 d}+\frac{(2 a e-c d x) \sqrt{a+c x^2}}{2 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{3 a \sqrt{c} \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d}-\frac{\left (a^2 e\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{c}+\frac{x^2}{c}} \, dx,x,\sqrt{a+c x^2}\right )}{c d^2}+\frac{(c (2 c d-3 a f)) \operatorname{Subst}\left (\int \frac{1}{1-c x^2} \, dx,x,\frac{x}{\sqrt{a+c x^2}}\right )}{2 d f}-\frac{\left (4 a c d^2 f^2+a^2 f^2 \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )+c^2 d^2 \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )\right ) \int \frac{1}{\left (e+\sqrt{e^2-4 d f}+2 f x\right ) \sqrt{a+c x^2}} \, dx}{d^2 f \sqrt{e^2-4 d f}}+\frac{\left (4 a c d^2 f^2+c^2 d^2 \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )+a^2 f^2 \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )\right ) \int \frac{1}{\left (e-\sqrt{e^2-4 d f}+2 f x\right ) \sqrt{a+c x^2}} \, dx}{d^2 f \sqrt{e^2-4 d f}}\\ &=-\frac{a e \sqrt{a+c x^2}}{d^2}+\frac{3 c x \sqrt{a+c x^2}}{2 d}+\frac{(2 a e-c d x) \sqrt{a+c x^2}}{2 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{3 a \sqrt{c} \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d}+\frac{\sqrt{c} (2 c d-3 a f) \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d f}+\frac{a^{3/2} e \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^2}+\frac{\left (4 a c d^2 f^2+a^2 f^2 \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )+c^2 d^2 \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 a f^2+c \left (e+\sqrt{e^2-4 d f}\right )^2-x^2} \, dx,x,\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{a+c x^2}}\right )}{d^2 f \sqrt{e^2-4 d f}}-\frac{\left (4 a c d^2 f^2+c^2 d^2 \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )+a^2 f^2 \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 a f^2+c \left (e-\sqrt{e^2-4 d f}\right )^2-x^2} \, dx,x,\frac{2 a f-c \left (e-\sqrt{e^2-4 d f}\right ) x}{\sqrt{a+c x^2}}\right )}{d^2 f \sqrt{e^2-4 d f}}\\ &=-\frac{a e \sqrt{a+c x^2}}{d^2}+\frac{3 c x \sqrt{a+c x^2}}{2 d}+\frac{(2 a e-c d x) \sqrt{a+c x^2}}{2 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{d x}+\frac{3 a \sqrt{c} \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d}+\frac{\sqrt{c} (2 c d-3 a f) \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d f}-\frac{\left (4 a c d^2 f^2+c^2 d^2 \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )+a^2 f^2 \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c \left (e-\sqrt{e^2-4 d f}\right ) x}{\sqrt{2} \sqrt{2 a f^2+c \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )} \sqrt{a+c x^2}}\right )}{\sqrt{2} d^2 f \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )}}+\frac{\left (4 a c d^2 f^2+a^2 f^2 \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )+c^2 d^2 \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{2} \sqrt{2 a f^2+c \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )} \sqrt{a+c x^2}}\right )}{\sqrt{2} d^2 f \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )}}+\frac{a^{3/2} e \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^2}\\ \end{align*}
Mathematica [C] time = 4.63904, size = 885, normalized size = 1.47 \[ \frac{-x \left (2 \sqrt{a} \sqrt{c} d f \sqrt{e^2-4 d f} \sqrt{c x^2+a} \sinh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right )+\sqrt{\frac{c x^2}{a}+1} \left (-2 c \sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \tanh ^{-1}\left (\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \sqrt{c x^2+a}}\right ) d^2-4 \sqrt{c} (c d-a f) \sqrt{e^2-4 d f} \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{c x^2+a}}\right ) d+2 a f \sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \tanh ^{-1}\left (\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \sqrt{c x^2+a}}\right ) d+2 c f \sqrt{e^2-4 d f} x \sqrt{c x^2+a} d+\left (2 c d^2+a \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )\right ) \sqrt{4 a f^2-2 c \left (-e^2+\sqrt{e^2-4 d f} e+2 d f\right )} \tanh ^{-1}\left (\frac{2 a f+c \left (\sqrt{e^2-4 d f}-e\right ) x}{\sqrt{4 a f^2-2 c \left (-e^2+\sqrt{e^2-4 d f} e+2 d f\right )} \sqrt{c x^2+a}}\right )+\sqrt{2} a e \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \tanh ^{-1}\left (\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \sqrt{c x^2+a}}\right )-a e^2 \sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \tanh ^{-1}\left (\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \sqrt{c x^2+a}}\right )-4 a^{3/2} e f \sqrt{e^2-4 d f} \tanh ^{-1}\left (\frac{\sqrt{c x^2+a}}{\sqrt{a}}\right )\right )\right )-4 a d f \sqrt{e^2-4 d f} \sqrt{c x^2+a} \, _2F_1\left (-\frac{3}{2},-\frac{1}{2};\frac{1}{2};-\frac{c x^2}{a}\right )}{4 d^2 f \sqrt{e^2-4 d f} x \sqrt{\frac{c x^2}{a}+1}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.288, size = 9912, normalized size = 16.4 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{2} + a\right )}^{\frac{3}{2}}}{{\left (f x^{2} + e x + d\right )} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + c x^{2}\right )^{\frac{3}{2}}}{x^{2} \left (d + e x + f x^{2}\right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \mathit{sage}_{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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